As I couldn't find any routines to do this...
I hacked these up in Perl an age ago... needed PHP versions so here they are (Ask if you want the Perl versions lazy..)
function validate_UPCABarcode($barcode)
{
// check to see if barcode is 12 digits long
if(!preg_match("/^[0-9]{12}$/",$barcode)) {
return false;
}
$digits = $barcode;
// 1. sum each of the odd numbered digits
$odd_sum = $digits[0] + $digits[2] + $digits[4] + $digits[6] + $digits[8] + $digits[10];
// 2. multiply result by three
$odd_sum_three = $odd_sum * 3;
// 3. add the result to the sum of each of the even numbered digits
$even_sum = $digits[1] + $digits[3] + $digits[5] + $digits[7] + $digits[9];
$total_sum = $odd_sum_three + $even_sum;
// 4. subtract the result from the next highest power of 10
$next_ten = (ceil($total_sum/10))*10;
$check_digit = $next_ten - $total_sum;// if the check digit and the last digit of the barcode are OK return true;
if($check_digit == $digits[11]) {
return true;
}
return false;
}function validate_EAN13Barcode($barcode)
{
// check to see if barcode is 13 digits long
if(!preg_match("/^[0-9]{13}$/",$barcode)) {
return false;
}$digits = $barcode;
// 1. Add the values of the digits in the even-numbered positions: 2, 4, 6, etc.
$even_sum = $digits[1] + $digits[3] + $digits[5] + $digits[7] + $digits[9] + $digits[11];
// 2. Multiply this result by 3.
$even_sum_three = $even_sum * 3;
// 3. Add the values of the digits in the odd-numbered positions: 1, 3, 5, etc.
$odd_sum = $digits[0] + $digits[2] + $digits[4] + $digits[6] + $digits[8] + $digits[10];
// 4. Sum the results of steps 2 and 3.
$total_sum = $even_sum_three + $odd_sum;
// 5. The check character is the smallest number which, when added to the result in step 4, produces a multiple of 10.
$next_ten = (ceil($total_sum/10))*10;
$check_digit = $next_ten - $total_sum;// if the check digit and the last digit of the barcode are OK return true;
if($check_digit == $digits[12]) {
return true;
}return false;
}
